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What will be the output of the following code?
function multiply(a, b = 2) {
return a * b;
}
function multiply(a, b = 2) {
return a * b;
}
console.log(multiply(3));
- a)5
- b)6
- c)3
- d)Error
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
What will be the output of the following code?function multiply(a, b =...
The 'multiply' function accepts two parameters, 'a' and 'b', with 'b' having a default value of 2. When called with 'multiply(3)', it uses the default value of 'b' (2) and returns the product of 'a' (3) and 'b' (2), which is 6.
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Community Answer
What will be the output of the following code?function multiply(a, b =...
Explanation:
The given code defines a function named "multiply" that takes two parameters, "a" and "b" with a default value of 2. Inside the function, it multiplies the values of "a" and "b" and returns the result.
In the console.log statement, the multiply function is called with a single argument, 3. Since the second argument is not provided, it will take the default value of 2.
Execution:
1. The function multiply is called with the argument 3.
2. Inside the function, the value of "a" is 3 and the value of "b" is 2 (default value).
3. The function multiplies 3 and 2, resulting in 6.
4. The function returns the value 6.
5. Finally, the value returned by the multiply function is printed to the console using console.log.
Output:
The output of the code will be 6.
Reasoning:
- When the multiply function is called with a single argument (3), it uses the default value of the second parameter (2) for the multiplication.
- Therefore, the code returns the product of 3 and 2, which is 6.
The given code defines a function named "multiply" that takes two parameters, "a" and "b" with a default value of 2. Inside the function, it multiplies the values of "a" and "b" and returns the result.
In the console.log statement, the multiply function is called with a single argument, 3. Since the second argument is not provided, it will take the default value of 2.
Execution:
1. The function multiply is called with the argument 3.
2. Inside the function, the value of "a" is 3 and the value of "b" is 2 (default value).
3. The function multiplies 3 and 2, resulting in 6.
4. The function returns the value 6.
5. Finally, the value returned by the multiply function is printed to the console using console.log.
Output:
The output of the code will be 6.
Reasoning:
- When the multiply function is called with a single argument (3), it uses the default value of the second parameter (2) for the multiplication.
- Therefore, the code returns the product of 3 and 2, which is 6.
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What will be the output of the following code?function multiply(a, b = 2) { return a * b;}console.log(multiply(3));a)5b)6c)3d)ErrorCorrect answer is option 'C'. Can you explain this answer?
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